N = 5
[C1] non-units [C2] #non-units lead to same
#solution for discriminant
[C3] #solution for discriminant
= non-units in C1
0 1 5
C2TC3 = #ways delta can be non-unit 5
Total non-singular EC over Z5 = 52 - #ways delta can be non-unit (C2TC3) = 20